A conical heap is formed when a farmer pours food grains on a ground .the slant height of heap is 35cm the circumference of the base is 132cm. what amount of tarpaulin is needed to cover the grains? Farmer goes to the orphanage and gives half of the food grains for the children living there. how much grains farmer donoted ? list values you learn from this act of the farmer?
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Given:
Circumference of thebase= 132 cm
slant height = 35 cm
We need to get the volume of the cone. We need the radius of the cone.
Circumference = 2 π r
r = circumference / 2π
r = 132 cm / 2 * 3.14
r = 132 cm / 6.28
r = 21 cm
Volume of the cone = 1/3 π r² √l² - r²
V = 1/3 * 3.14 * (21cm)² * √(35² - 21²)
V = 1/3 * 3.14 * 441cm² * √1225-441cm
V = 461.58cm² * √784cm
V = 461.58cm² * 28cm
V = 12,924.24 cm³
Surface area of the cone to know the measurement of the tarpaulin needed.
Surface area = π r l + πr²
SA = 3.14 * 21cm * 35cm + 3.14 (21cm)²
SA = 2,307.9 cm² + 3.14 (441cm²)
SA = 2,307.9 cm² + 1,384.74 cm²
SA = 3,692.64 cm²
Tarpaulin = 3,692.64 cm²
Half of the grain given to orphanage = 12,924.24 cm³ ÷ 2 = 6,462.12 cm³
Circumference of thebase= 132 cm
slant height = 35 cm
We need to get the volume of the cone. We need the radius of the cone.
Circumference = 2 π r
r = circumference / 2π
r = 132 cm / 2 * 3.14
r = 132 cm / 6.28
r = 21 cm
Volume of the cone = 1/3 π r² √l² - r²
V = 1/3 * 3.14 * (21cm)² * √(35² - 21²)
V = 1/3 * 3.14 * 441cm² * √1225-441cm
V = 461.58cm² * √784cm
V = 461.58cm² * 28cm
V = 12,924.24 cm³
Surface area of the cone to know the measurement of the tarpaulin needed.
Surface area = π r l + πr²
SA = 3.14 * 21cm * 35cm + 3.14 (21cm)²
SA = 2,307.9 cm² + 3.14 (441cm²)
SA = 2,307.9 cm² + 1,384.74 cm²
SA = 3,692.64 cm²
Tarpaulin = 3,692.64 cm²
Half of the grain given to orphanage = 12,924.24 cm³ ÷ 2 = 6,462.12 cm³
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