A conical pit of top diameter 3.5m is 12m deep .find its slant height on volume
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hiii!!!
here's ur answer...
given the diameter of the conical pit = 3.5m
therefore radius is = 3.5/2
= 1.75m
height (deep) = 12m
let the slant height of the conical pit be c, radius be a and height be b.
==> c² = a² + b²
==> c² = 1.75² + 12²
==> c² = 3.0625 + 144
==> c² = 147.0625
==> c = √147.0625
==> c = 12.12 (approximately)
hence, the slant height of the conical pit is 12.12m (approximately)
volume of the conical pit = 1/3πr²h
= 1/3 × 22/7 × 1.75 × 1.75 × 12
= 808.5/21
= 38.5m³
hope this helps..!!
here's ur answer...
given the diameter of the conical pit = 3.5m
therefore radius is = 3.5/2
= 1.75m
height (deep) = 12m
let the slant height of the conical pit be c, radius be a and height be b.
==> c² = a² + b²
==> c² = 1.75² + 12²
==> c² = 3.0625 + 144
==> c² = 147.0625
==> c = √147.0625
==> c = 12.12 (approximately)
hence, the slant height of the conical pit is 12.12m (approximately)
volume of the conical pit = 1/3πr²h
= 1/3 × 22/7 × 1.75 × 1.75 × 12
= 808.5/21
= 38.5m³
hope this helps..!!
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