a conical tank of radius 7m and height 24m is to be made find the cost of 5m wide cloth required at the rate 50 rupees per meter
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Answered by
1
Let the slant height of the cone be 'l' meters.
height = 24 m and radius = 7 m.
Then according to the question.
l² = h² + r²
l² = 24² + 7²
l² = 576 + 49
l² = 625
l = √625
l = 25 m
So, the slant height of the cone is 25 m.
Now,
Curved Surface Area of the cone = πrl
= 22/7*7*25
CSA = 550 sq m
Now, length of the cloth used = Area/ width of the cloth
= 550/5
Length of the cloth used = 110 m
Cost of cloth = Rs. 50per meter
Total cost of clothe used = 110*50
= Rs. 5500
height = 24 m and radius = 7 m.
Then according to the question.
l² = h² + r²
l² = 24² + 7²
l² = 576 + 49
l² = 625
l = √625
l = 25 m
So, the slant height of the cone is 25 m.
Now,
Curved Surface Area of the cone = πrl
= 22/7*7*25
CSA = 550 sq m
Now, length of the cloth used = Area/ width of the cloth
= 550/5
Length of the cloth used = 110 m
Cost of cloth = Rs. 50per meter
Total cost of clothe used = 110*50
= Rs. 5500
Answered by
3
Answer:
let the slant of height of a cone be “l”
metre
height = 24m. and radius = 7m
the A/Q
l^2= h^2 + r^2
l^2 = 24^2 + 7^2
l^2 = 625
l. = √625
l. = 25
so the slant of height of cone is 25
now
CSA of a cone = πrl
22/7×7/25
550sqm
now length = area/ width of length
550/5
110
cost of cloths = RS 50 per metre
total cost of cloths used 110 × 50
5500
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