A conical tent has a radius of 5 cm and height of 25 cm what is the volume of the air enclosed by the tent ? With word solution
Answer please its urgent
Answers
Answer:
654.17cm³ volume of the air enclosed by the tent whose radius of 5 cm and height of 25 cm.
Step-by-step explanation:
r = 5cm h = 25cm
V = πr²h/3
= 3.14(25)(25)/3
= 1962.5/3
= 654.17cm³
Concept:
A cone is a 3 -dimensional geometric shape that reduces its thickness smoothly from a flat base to a point called the vertex.
Volume of cone refers to the space occupied inside the cone.
The formula for volume of cone is:
V = 1 / 3( π r² h )
Given:
We are given that:
radius = 5 cm and height = 25 cm
Find:
We need to find the volume of the volume of the air enclosed by the tent
Solution:
Volume of cone is:
V = 1 / 3( π r² h )
Substituting the value of r and h :
V = 1 / 3( π (5)² (25) )
Solving the expression:
V=625/3 π.
Put π=3.14:
V=654.167 cm³.
Therefore, the volume of the air enclosed by the tent is 654.167 cm³.
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