a conical tent is 10 M high and the radius of its base is 24 M. find the cost of the Canvas required to make the tent if the cost of 1 metre square Canvas is Rs70
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6
Right circular cone:
If a right angled triangle is revolved about one of the two sides forming a right angle keeping the other side fixed in position then the solid so obtained by segments is called right circular cone.
Slant height:
The length of the line segment joining the vertex to any point on a circular edge of the base is called the slant height of the cone.
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Given:
Radius of the base (r) = 24 mHeight of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know thatl²= r²+h² l = √h²+r² l = √10²+ 24²l = √100 + 576l = 26 m
Slant height (l)= 26 m
(ii) Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m2 canvas = ₹70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹137280
Hence, required cost of the Canvas is ₹137280
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Hope this will help you....
If a right angled triangle is revolved about one of the two sides forming a right angle keeping the other side fixed in position then the solid so obtained by segments is called right circular cone.
Slant height:
The length of the line segment joining the vertex to any point on a circular edge of the base is called the slant height of the cone.
----------------------------------------------------------------------------------------------------
Given:
Radius of the base (r) = 24 mHeight of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know thatl²= r²+h² l = √h²+r² l = √10²+ 24²l = √100 + 576l = 26 m
Slant height (l)= 26 m
(ii) Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m2 canvas = ₹70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹137280
Hence, required cost of the Canvas is ₹137280
=========================================================
Hope this will help you....
Answered by
4
Hi there!
Given:
Radius of the base (r) = 24 m
Height of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know that,
l²= r² + h²
l = √h² + r²
l = √10² + 24²
l = √100 + 576
l = 26 m
Slant height (l)= 26 m
Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m² canvas = ₹ 70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹ 1, 37, 280
Hence,
required cost of the Canvas is ₹ 1, 37, 280
[ Thank you! for asking the question. ]
Hope it helps!
Given:
Radius of the base (r) = 24 m
Height of the conical tent (h) = 10 m
Let l be the slant height of the cone.
We know that,
l²= r² + h²
l = √h² + r²
l = √10² + 24²
l = √100 + 576
l = 26 m
Slant height (l)= 26 m
Canvas required to make the conical tent = Curved surface of the cone
Cost of 1 m² canvas = ₹ 70
C.S.A of tent= πrl
= (22/7 × 24 × 26)
= 13728/7 m²
∴ Cost of canvas = ₹ 13728/7 × 70 = ₹ 1, 37, 280
Hence,
required cost of the Canvas is ₹ 1, 37, 280
[ Thank you! for asking the question. ]
Hope it helps!
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