A conical tent is 10m high and the radius of its base is 24m. Find 1. slant height of the tent and 2. cost of the canvas required to make the tent, if the cost of 1m^2 canvas is Rs. 70.
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Height of conical tent is 10m
Radius of conical tent is 24m
let slant height of tent is l m.
we know rhat
= l^2=h^2+r^2
=l^2=10^2+24^2
=l^2=100+576
=l^2=676
=l=√676
=l=26m.
Now,cost of canavas required to make the tent= 1m^2=70Rs.
Firstly,Area of cone= πr(r+√h^2+r^2)
=22/7×24(24+√10^2+24^2)
=22/7×24(24+100+576)
=22/7×24(24+676)
=22/7×24×700
=22×24×100 m^2
=52800m^2
Cost required= 1m^2=70Rs.
=52800m^2×70Rs.
=3696000Rs. Answer.
MARK BRAINLIEST...
Radius of conical tent is 24m
let slant height of tent is l m.
we know rhat
= l^2=h^2+r^2
=l^2=10^2+24^2
=l^2=100+576
=l^2=676
=l=√676
=l=26m.
Now,cost of canavas required to make the tent= 1m^2=70Rs.
Firstly,Area of cone= πr(r+√h^2+r^2)
=22/7×24(24+√10^2+24^2)
=22/7×24(24+100+576)
=22/7×24(24+676)
=22/7×24×700
=22×24×100 m^2
=52800m^2
Cost required= 1m^2=70Rs.
=52800m^2×70Rs.
=3696000Rs. Answer.
MARK BRAINLIEST...
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