Math, asked by stitlingstar16, 19 days ago

a conical tent is 12 m high and base radius is 16 find the cost of canvas required to make the tent if cost if 1m² is 70 rupees​

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Answered by ImperialGladiator
24

Answer:

Rs.70336

Explanation:

A conical tent of,

  • height (h) = 12m
  • radius of the base (r) = 16m

Find the cost of canvas required to make the tent is the rate is Rs.70/

Here,

We need to find the curved surface area of the tent to find out the total cost.

Curved surface area of the tent is given by,

 \boldsymbol{ = \pi rl}

Finding \boldsymbol l (slant height) :-

 =  \sqrt{ {r}^{2} +  {h}^{2}  }

 =  \sqrt{ {(16)}^{2} +  {(12)}^{2}  }

 =  \sqrt{256 + 144}

 =  \sqrt{400}

 \rm = 20 m

Calculating the curved surface area,

 = \pi rl

 =  3.14  \times 16 \times 20 [taking π as 3.14]

 \rm = 1004.8 {m}^{2}

Curved surface area is 1004.8m²

Now then,

Total cost for construction :-

= rate × area

= 70 × 1004.8

= Rs.70336

Required answer: Rs.70,336

___________________________

Formulae:

  • Slant height =  =  \sqrt{ {r}^{2} +  {h}^{2}  }
  • Curved surface area =  \boldsymbol{ = \pi rl}

Where,

  • r denotes the base radius.
  • h is the height.
Answered by Anonymous
39

Given :

Height of the tent (h) = 12 m

Radius of the base (r) = 16 m

The cost of 1 m² canvas

  • = 70 Rs

To Find :

  • The Slant height

  • Cost of canvas required to make the tent

Formula used :

 \rm \: l =  \sqrt{ {h}^{2} +  {r}^{2}  }

 \rm \: Curved  \: surface  \: area \:  of  \: cone = \pi \: r \: l \:

Solution :

 \rm \:  \because \: The \:  Slant  \: height ,l =  \sqrt{ {h}^{2}  +  {r}^{2} }

 \rm \implies  \:  \sqrt{ {12}^{2} +  {16}^{2}  \: m }

 \rm \implies \:  \sqrt{144 + 256 \: m}

 \rm \implies \:  \sqrt{400}

 \rm \implies \: 20 \: m

Thus,

  • Required slant height of the tent is 20 m

\rm \:  \because \: The \:  Curved  \:Surface \:  area  \: of  \: cone ,l =  \pi \: r \: l

\rm \:  \therefore\: The \:  Area \: of \:  canvas \:  required ,

 \rm \implies \:  \dfrac{22}{7}  \times 16 \times 20 \:  {m}^{2}

 \implies \:  \dfrac{7040}{7}

 \rm \: \therefore  \: The \:  cost \:  of \:  canvas

 \implies  \rm \: \: 70 \: Rs \times  \dfrac{7040}{7}

 \implies  \rm\: 10  \: Rs \: \times 7040

 \rm \implies \boxed{70,400 \:  Rs}

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