Question

a conical tent is 16m high and radius of base is 24cm Find the C.SA of the tent​

Answer 1

GiveN:

• Height =16m
• Radius of base=24cm

FinD:

• CSA of tent

SolutioN:

Height = 16m

Radius = 24cm=0.24m

$Slant height (l) = \sqrt{ {h}^{2} + {r}^{2} }$

$\sqrt{ {16}^{2} + {0.24}^{2} }$

$\sqrt{ 256 + 0.0566}$

$\sqrt{16.002m}$

L= 16.002m

CSA of tent = πrl

$CSA of tent = \frac{22}{7} \times 16.002 \times 0.24$

CSA = 12.07m

Answer 2

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Given:

• height of conical tent = 16m =1600cm
• radius of conical tent = 24cm

To find:

Curved Surface Area of conical tent

Solution:

$\\ \setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(18,1.6){\sf{24cm}}\put(9.5,10){\sf{1600cm}}\put(18,13){\sf{1600.2cm}} \end{picture}$

slant height (l) = $\displaystyle \sqrt{h^2+r^2}$

l = $\displaystyle \sqrt{1600^2+24^2}$

l = $\displaystyle \sqrt{2560000+576}$

l = $\displaystyle \sqrt{2560576}$

l $\approx$ 1600.2

CSA of cone = $\pi*r*l$

CSA of cone = $3.14*24*1600.2$

CSA of cone $\approx 120591.072$

CSA of cone = 120591.072 cm^2

CSA of cone $\approx 12.06m^2$

So,the CSA of the tent is 12.06m^2

Formula Used:

• Volume of cone = $\pi*r*l$

Learn More:

• Volume of cylinder = πr²h

• T.S.A of cylinder = 2πrh + 2πr²

• Volume of cone = ⅓ πr²h

• C.S.A of cone = πrl

• T.S.A of cone = πrl + πr²

• Volume of cuboid = l × b × h

• C.S.A of cuboid = 2(l + b)h

• T.S.A of cuboid = 2(lb + bh + lh)

• C.S.A of cube = 4a²

• T.S.A of cube = 6a²

• Volume of cube = a³

• Volume of sphere = (4/3)πr³

• Surface area of sphere = 4πr²

• Volume of hemisphere = ⅔ πr³

• C.S.A of hemisphere = 2πr²

• T.S.A of hemisphere = 3πr²