Question

A conical tent is 48m high and the diameter of its base 28m find the surface area

Answer 1

height of tent(h)=48m

diameter of base=28m

radius(r)= 28/2m

r = 14m

surface area of conical tent= $\pi$rl

l(slant height) =$\sqrt{r^{2}+h^{2}$

l= $\sqrt{(14)^{2} +(48)^{2}}$

l=$\sqrt{196+784}$

l=31.30m

surface area=22/7*14*31.30

=22*313/5

=6886/5

=1377.2

surface area of conical tent=1377.2$m^{2}$