Question

a conical tent is made of 4.5 m wide tarpaulin, vertical height of tent is 4 m &base radius is 3 m. find the length of tarpaulin used assuming that 10% of extra material is required for stitching and wastage in cutting. π = 3.14.......answer fast kal question check karwana hai....

Answer 1

Applying Pythagors' theorem,
slant height, l² = r² +h²
⇒ l² = 3² +4²
⇒l² =25
⇒slant height = 5 m
now, curved surface area = π× r×l
                                          = 3.14×3×5
                                          = 47.1 m²
now, 10% extra material is required for stitching and wastage = 0.1 ×47.1 = 4.71 m²
total area = 47.1 +4.71
                =51.81 m²
now, L×B = 51.81
⇒Length ,L = 51.81/4.5
                   = 11.51 m

Answer 2

Thank you for asking this question. Here is your answer:

R = 3m

H = 4m

l = √r² + h² = 5m

CSA = πrl = 47.10m²

So the area of extra material would be: (10%) = 10/100 x 47.10

Total Area = 47.10 + 4.71

= 51.81 m²

We already have the breadth, we need to find the length

So we will use the following formula:

Area = L x B

51.81 = L x 4.5 m

L = 11.51 m

If there is any confusion please leave a comment below.