Question

a conical tent is to accommodate 11 persons each person must have four square metres of space on the ground what will be the curved surface area of conical tent if its height is 15​

Answer 1

Answer:

Height of conical tent= 15m

Area occupied by each person = 4m^2

Area occupied by 11 persons

$= 11 \times 4 = {44m}^{2}$

If the radius of base is r

then

$\pi {r}^{2} = 44 \\ \\ {r}^{2} = \frac{44}{\pi} = \frac{44}{22} \times \: 7 \\ \\ = \frac{ { \cancel{44}} \: \: ^{2} }{ \cancel{22}} \times 7 \\ \\ = 2 \times 7 = 14m$

${r}^{2} = 14m \\ \\ \to \: r = 3.74m$

Let l be slant height of conical tent

$l = \sqrt{ {r}^{2} + {h}^{2} } = \sqrt{14 + {(15)}^{2} } \\ \\ = \sqrt{239 } \\ \\ = 15.45m \\ \\ \rule{200pt}{5pt}$

Therefore,

Curved surface area of conical tent

$= \pi rl \\ \\ = \frac{22}{7} \times 3.74 \times 15.45 \\ \\ = {181.60m}^{2}$

$\rule{200pt}{5pt}$

Hope it helps you from my side

:)

Answer 2

Answer:

Curved surface area of conical tent

= πrl = 7/22 × 3.74 × 15.45 = 181.60m^2.

$thanks$