a conical tent is to accomodate 22 persons. each person must have 5m^2 of the space on the ground and 30m^3 of air to breath. find the height of the cone
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Area of base = 11×4=44 m2
πr2=44 m2
Volume of the cone = 11×20=220 m3
31πr2h=220 m3
Therefore,
πr231πr2h=44220
3h=5
h=15 m
Answered by
44
Area of base = 11 × 4 = 44 m2
nr2 =44m2
Volume of cone = 11 × 20 = 220 m3
31πr 2h = 220 m3
Therefore ,
πr 231 πr2h = 44220
3h = 5
H = 15 m
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