Question

A conical tent of diameter 7m and height 3m is to be maid by tarpaulin how much length of tarpaulin of width 1m is required for tent​?

Answer 1

QuestioN :

A conical tent of diameter 7m and height 3m is to be maid by tarpaulin how much length of tarpaulin of width 1m is required for the tent​?

GiveN :

• A conical tent of diameter 7m and height 3m is to be maid by a tarpaulin.

To FiNd :

• How much tarpaulin of width 1m is required for the tent​.

ANswer :

50.71 m of tarpaulin is required for the tent.

SolutioN :

The diameter of conical tent = 7m

⇒ Radius of conical tent = 7/2 = 3.5 m

⇒ Height of tent = 3 m

Therefore,

⇒ Slant height, l = √[(3.5)² + (3)²]

⇒ l = √[12.25 + 9]

⇒ l = √[21.25]

⇒ l = 4.61 m

Now, the tarpaulin is the CSA of the tent.

⇒ CSA of cone = πrl

⇒ CSA of tent = 22/7 × 3.5×  4.61

⇒ CSA of tent = 50.71 m²

Now,

⇒ Area of tarpaulin materials = CSA of the tent

⇒ Length × 1 = 50.71

⇒ Length = 50.71/1

⇒ Length = 50.71 m

∴Hence, 50.71 m of tarpaulin is required for the tent.

Answer 2

Answer:

The diameter of conical tent = 7m

⇒ Radius of conical tent = 7/2 = 3.5 m

⇒ Height of tent = 3 m

Therefore,

⇒ Slant height, l = √[(3.5)² + (3)²]

⇒ l = √[12.25 + 9]

⇒ l = √[21.25]

⇒ l = 4.61 m

Now, the tarpaulin is the CSA of the tent.

⇒ CSA of cone = πrl

⇒ CSA of tent = 22/7 × 3.5×  4.61

⇒ CSA of tent = 50.71 m²

Now,

⇒ Area of tarpaulin materials = CSA of the tent

⇒ Length × 1 = 50.71

⇒ Length = 50.71/1

⇒ Length = 50.71 m

∴Hence, 50.71 m of tarpaulin is required for the tent.

Hope this will help you :)