a conical vessel of radius 14 cm and height 7 cm is full of water. a sphere is dipped into it and it completely gets immersed making 1/8th part of the water splash out of the vessel. what is the radius of the sphere?
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Given:-
radius of cone = 14 cm
height of cone = 7cm
volume of cone = πr2h
= πr2h
= π*14*14*7
=22*14*14
= 4312 cm3
volume of water splashed out = volume of sphere
volume of water splashed out = 1/8πr2h
volume of water splashed out = 4312/8
volume of water splashed out = 539 cm2
volume of sphere = 4/3*πr3
volume of sphere = 4/3*πr3= 539
r3 = 539/π*3/4
r3 = 343/2*3/4
r3 = 1029/8
r =3.5 √3
r = 3.5*1.73
radius of sphere = 6.05 cm
radius of cone = 14 cm
height of cone = 7cm
volume of cone = πr2h
= πr2h
= π*14*14*7
=22*14*14
= 4312 cm3
volume of water splashed out = volume of sphere
volume of water splashed out = 1/8πr2h
volume of water splashed out = 4312/8
volume of water splashed out = 539 cm2
volume of sphere = 4/3*πr3
volume of sphere = 4/3*πr3= 539
r3 = 539/π*3/4
r3 = 343/2*3/4
r3 = 1029/8
r =3.5 √3
r = 3.5*1.73
radius of sphere = 6.05 cm
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