Question

a conical vessel whose internal depth is 42 cm and and internal diameter is 48cm is full of water. if 1 cubic dm of water weighs 1 kg wt, then the weight if water in the conical vessel is​

Answer 1

Answer:

Step-by-step explanation:

Volume of water in the conical vessel will be equal to the volume of water in the cylindrical vessel.

Volume of a Cylinder of Radius "R" and height "h" =πR  

2

h

Volume of a cone =  

3

1

​  

πr  

2

h, where r is the radius of the base of the cone and h is the height.

Hence,  

7

22

​  

×10×10×h=  

3

1

​  

×  

7

22

​  

×5  

2

×24

⇒h=2 cm  

Hence, height of water in the cylindrical vessel is 2 cm.

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Answer 2

Step-by-step explanation:

Volume of conical vessel =

3 πr²

h= 31 ×3.74×1×10×48=5024cm

Let height of cylindrical vessel be 'h' then

⇒ Volume of cylindrical vessel = Volume of water

⇒πr²

h=5024⇒3.14×(20) 2

×h=5024⇒h=4cm

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