a conical vessel whose internal depth is 42 cm and internal diameter is 48 cm is full of water .if 1 cubic dm of water weight 1 kg wt then the weight of water in the coniCal vessel is
Answers
Given :- a conical vessel whose internal depth is 42 cm and internal diameter is 48 cm is full of water .if 1 cubic dm of water weight 1 kg wt then the weight of water in the conical vessel is ?
Solution :-
we know that,
- Volume of cone = (1/3) * π * (radius)² * height .
- radius = (diameter/2) .
So,
- radius of conical vessel = (48/2) = 24 cm.
- height of conical vessel = 42 cm.
Than,
→ Volume of conical vessel = (1/3) * π * (24)² * 42
→ Volume = (1/3) * (22/7) * (576 * 42)
→ Volume = (22 * 576 * 42)/ 21
→ Volume = 44 * 576
→ Volume = 25,344 cm³.
Now, we know that,
- 1000 cm³ = 1dm³ .
Therefore,
→ 1000 cm³ = 1 dm³
→ 1 cm³ = (1/1000) dm³
→ 25344 cm³ = (1/1000) * 25344 = 25.344 dm³.
Now, given that,
→ 1 dm³ weights = 1 kg.
→ 25.344 dm³ weights = 25.344 kg. (Ans.)
Hence, the weight of water in the conical vessel is 25.344 kg.
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