A conical vessel whose internal dimentions are 105 cm deep and 120 cm in diameter is full of water . if a cubic decimetre of water weights 1kg 500g . find the weight of the water contained in the vessel..
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Answers
Answer:
Given depth ( Height ) of conical vessel = 105 cm = 10.5 decimeter ( We know 1 cm = 0.1 decimeter )
And
Diameter of conical vessel = 120 cm , So
Radius of conical vessel = 60 cm = 6 decimeter
We know : Volume of cone = πr^2h/3 , So
Volume of conical vessel =22/7× 6^2 × 10.5/3 = 22×36× 1.5/3= 22×12× 1.5 = 396 cubic decimeter
Given 1 cubic decimeter = 1 kg 500 gm = 1.5 kg ( We know 1 kg = 1000 gm )
Therefore,
Weight of water contained in the vessel = 396 × 1.5 = 594 kg
Step-by-step explanation:
hope it helps you
Answer:
594kg (a)
Step-by-step explanation:
internal dimensions:
height = 105cm = 105/10 = 10.5decimeters(dm)
diameter = 120cm
radius = 60cm = 6dm
volume of conical vessel = 1/3x22/7xr^2xh
= 1/3x22/7x6x6x10.5
we get the answer as:
= 396 cubic decimeter
as per the question 1 dm^3 = 1 kg 500g = 1.5kg
for 396 dm^3 = 396 x 1.5 = 594 kg