Question

A conical vessel, with base radius 5 cm and height 24 cm, is full of water. This water is emptied into a cylindrical vessel of base radius 10 cm. Find the height to which the water will rise in the cylindrical vessel. (Use $\pi = \frac{22}{7}$ )

Answer 1

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Answer 2

Given :-

base radius of the conical vessel = 5cm

height of the conical vessel = 24cm

volume of the conical vessel = 1/3πr²h

= 1/3 * 22/7 * 5 * 5 * 24

= 550/7 * 8

= 4400/7cm³

ATQ, the water in the conical vessel is emptied into a cyindrical vessel of radius 10cm.

∴ volume of the conical vessel = volume of the cylindrical vessel

⇒ 4400/7cm³ = πr²h

⇒ 4400/7 = 22/7 * 10 * 10 * h

⇒ 4400/7 = 2200/7 * h

⇒ 4400/7 * 7/2200 = h

⇒ 2 = h

⇒ h = 2cm

hence the height of the cylindrical vessel is 2cm.