A conical vessel with base radius 5cm and height 24cm is full of water. This water is emptied into a cylindrical vessel of base radius 10cm. Find the height to which the water will rise in the cylindrical vessel.
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Internal radius of conical vessel = 5 cm
Height = 24 cm
Since the conical vessel is full of water, so volume of water = volume of vessel
So, volume of water = 13πr2h = 13×227×52×24 = 44007 cm3
Now, this volume of water is emptied in a cylindrical vessel.
So, suppose the height of level of water in the cylindrical vessel is h.
and radius of base of cylindrical vessel = 10 cm
So, volume of water in cylindrical vessel up to height h = π×102×h = 44007 cm3
⇒227×100×h = 44007⇒h = 440022×100 = 2
Therefore, height of water level in cylindrical vessel = 2 cm
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Height = 24 cm
Since the conical vessel is full of water, so volume of water = volume of vessel
So, volume of water = 13πr2h = 13×227×52×24 = 44007 cm3
Now, this volume of water is emptied in a cylindrical vessel.
So, suppose the height of level of water in the cylindrical vessel is h.
and radius of base of cylindrical vessel = 10 cm
So, volume of water in cylindrical vessel up to height h = π×102×h = 44007 cm3
⇒227×100×h = 44007⇒h = 440022×100 = 2
Therefore, height of water level in cylindrical vessel = 2 cm
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Volume of water in conical vessels=>
1/3 × 22/7 × 25 × 24 cm^3
▶Let h be the height to which the water will rise in the cylindrical vessels!
Volume of conical vessels = Volume of cylindrical vessels
▶1/3×22/7×25×24 = 22×10×10×h
So, h= 2 cm...Ans..✔
1/3 × 22/7 × 25 × 24 cm^3
▶Let h be the height to which the water will rise in the cylindrical vessels!
Volume of conical vessels = Volume of cylindrical vessels
▶1/3×22/7×25×24 = 22×10×10×h
So, h= 2 cm...Ans..✔
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