Question

A conical vessel with the base radius 5cm and height 24cm is full of water is emptied into a cylinder vessel of base radius 10cm find the height to which the water will rise in the cylindrical vessel​

Answer 1

Refer below for the answer to your question

Answer 2

Solution

r1=5cm

h2=24cm

therefore..

•now if it is poured into a conical vessel then...

$v1 = \frac{1}{3} \pi \: (r1) {}^{2} \times( h1) \\ v2 = \frac{1}{3} \pi \:( r2) {}^{2} \times (h2) \\ \\ now..... \\ \frac{v1}{v2} = (\frac{r1}{r2} ) {}^{2} \times \frac{h1}{h2} \\ 1 =( \frac{5}{10} ) {}^{2} \times \frac{24}{h2} \\ = > h2 = 6 \: cm$

therefore,the height will be 2cm...

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•now if it is poured into a cylindrical vessel then...

v2=π(r2)²(h2)

therefore...

v1=v2

π(r1)²(h1)/3=π(r2)²(h2)

=>h2=(r1/r2)²×(h1/3)=(5/10)²×(24/3)=2cm

therefore,the height will be 2cm...

.....Hope this helps you....