Question

a constant contact force of 20 Newton acts on a wooden block of mass 5 kg for a duration of 5 seconds if the block was initially moving with a velocity of 5 metre per second what is the final velocity acquired by it​

Answer 1

Explanation:

ANSWER

Given,

mass=5kg

t

1

=2s

Initial velocity u=3m/s

Final velocity v=7m/s

t

2

=5s

So,

Let the Force be F

Let the acceleration be a

So,

a=

t

(v−u)

=

2

(7−3)

=2m/s

2

So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s

Hope it is helpful to you!!!