A constant electric field \vec{E}=4icap exists in space. A particle of mass 2 kg and charge +2.5 C starts from rest from the origin. What is its speed when it is at x = 22.5m?
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2
Answer:
15
Step-by-step explanation:
F= E*Q
=4*2.5
=10 N
a=F/m=10/2 =5m/s²
v²-u²=2as
v²-0=2*5*22.5
⇒v=15
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