Question

A constant force 10 N pushes three blocks A, B and Con a smooth horizontal smooth surface. The masses of the
blocks are 2 kg, 3 kg. 5 kg respectively. The ratio of normal reaction between A and B to the normal reaction
between B and C.​

Answer 1

Answer:

Explanation:

Given

mass of A $m_a=2 kg$

mass of B $m_b=3 kg$

mass of C $m_c=5 kg$

Force F=10 N

net acceleration of system is $a_{net}=\frac{F}{m_a+m_b+m_c}$

$a=\frac{10}{2+3+5}=1 m/s^2$

$F-N_1=m_ca$

$N_1=F-m_ca$

$N_1=10-5\times 1=5 N$

$N_2=m_a\times a$

$N_2=2\times 1=2 N$

reaction between A & B is 2 N

Reaction between B & C is 5 N