Question

A constant force (4i+ 2j + 3k ) acts on a body to produce displacement (11i+ 11j + 25k )then work done by force​

Answer 1

Answer:

141J

Explanation:

Work done =  F.dr

Here which equals to

(4i+ 2j + 3k ). (11i+ 11j + 25k ) J

= (44+22+75)J

=141J

Answer 2

Given :-

A constant force (4i+ 2j + 3k ) acts on a body to produce displacement (11i+ 11j + 25k )

To Find :-

Work done

Solution :-

We know that

$\sf Work \; done= Force. Displacement$

$\sf Work \; done = (4i \times 11i) + (2j\times 11j)+(3k \times 25k)$

$\sf Work \; done = 44+22+75$

$\sf Work \; done = 141$

Therefore,

Work done is 141 J