Question

A constant force 50N applied on a body of mass 20kg initially moving with a speed of 15m/s How long does the body take to stop.

Answer 1

Answer:

t = 6sec

Explanation:

-50 = ma = 20a

a = -50/20

a = -2.5m/s

Using first eqn of motion _

V = u + at

0 = 15 + (-2.5)t {here v = 0}

2.5t = 15

t = 15/2.5

t = 6s