Question

A constant force act on a body on a object of mass 5kg for 10 second and increase the velocity from 5m /s to 10m/s .find the force applied.
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Answer 1

Given :-

• Mass of body = 5 kg
• Force acted for = 10s
• initial velocity = 5 m/s
• Final velocity = 10 m/s

To find :-

• Force = ?

Solution :-

Firstly finding acceleration

Using the first eq of motion

v = u + at

Where

• v → final velocity = 10 m/s
• u → initial velocity = 5 m/s
• a → acceleration = ?
• t → time taken change velocity = 10s

Substituting the values we have

→ 10 = 5 + a(10)

→ 10 - 5 = 10a

→ 5 = 10 a

→ a = 5/10 = ½

→ acceleration = 0.5 m/s²

Now , finding force acted on the body

F = m × a

Where

• F → force = ?
• m → mass = 2 kg
• a → acceleration = 1/2 m/s²

Substituting the values we have

→ F = 2 × ½

→ Force acted = 1 N

Hence , force acted on the body = 1 N

Answer 2

Answer is given in the pic.