Question

a constant force act on an object of mass 10 kg for duration of 4 second. it increases the object's velocity from 4 metre per second to 8 m per second find the magnitude of the applied force now if the force was applied for a duration of 8 second what would be the final velocity of the object
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Answer 1

Answer:

Mass of an object m = 10 kg initial velocity u = 2 ms-1 Final velocity v = 8 ms-1 We know, force F = m ( v − u ) t m(v−u)t F = 10 ( 8 − 2 ) 4 10(8−2)4 = 10 × 6 4 10×64 = 15 NRead more on Sarthaks.com - https://www.sarthaks.com/942315/constant-force-acts-object-mass-for-duration-it-increases-the-objects-velocity-from-to-ms