Question

A constant Force act on an object of mass 2 kg for 10sec and increase its velocity from 5to 10m/s.find the magnitude of applied force. If this force was applied for a duration of 15s what would be the velocity.

Answer 1

Explanation:

v=u+at

10=5+a×10

a=1/2

now

force=m×a

= 2×1/2

=1N

v=u+at

v=5+1/2×15

v =12.5m/s