Question

a constant force act on an object of mass 5 kg for a duration of 2 second it increases the object velocity from 3 metre per second to 7.7 find the magnitude of the force applied​

Answer 1

Answer:

Force = 11.75 N

Step-by-step explanation:

Given :-

m = 5kg

t = 2s

initial velocity(u) = 3 m/s

final velocity (v) = 7.7 m/s

According to the first equation of motion

acceleration = (v - u) /t

=> a = (7.7 - 3)/2

=> a = 2.35 m/s^2

Now,

Force = mass*acceleration ( Newton's 2nd law of motion)

F = 5*2.35

= 11.75 N