Physics, asked by llUniqueStarll, 2 days ago

A constant force acting on a body of mass 3.0 kg changes its speed from 0.2m/s-¹ to 3.5 m s-¹ in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force ?

Answers

Answered by Anonymous
39

\huge\colorbox{white}{ \colorbox{white}{\colorbox{white}{Question}}}

A constant force acting on a body of mass 3.0 kg changes its speed from 0.2m/s-¹ to 3.5 m s-¹ in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force ?

\huge\colorbox{white}{ \colorbox{white}{\colorbox{white}{Answer}}}

Given :

  • u = 2m/s^{-1}
  • m = 3kg
  • v = 3.5m/s^{-1}
  • v = 25 s

To Find :

 \small\sf\colorbox{black}{\colorbox{red}{\colorbox{white}{Magnitude\: and\: Direction\: of\: Force}}}

 \color{red} {To\: Find\: FORCE}

\small\sf\colorbox{black}{ \colorbox{white}{\colorbox{white}{Formula\: used\: = \: F \: = \: m\: ×\: a}}}

\huge\sf\star Calculation

Since ,

\tt\:\small\color{black}\boxed{\colorbox{white}{v\: = \: u\ +\: at}}

Therefore,

\sf\huge\implies  \tt \:3.5 = 2 + a × 25

\sf\huge\implies \tt \: a = \frac{3.5}{25} = 0.06 m\s^-2

From formula

\sf\huge\implies F = 3 × 0.06 = 0.18 N

Since , the applied force increases the speed of the body ,it acts in the direction of motion

Similar questions