Question

A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m s⁻¹ per second to 3.5 m s⁻¹ in 25 s. The direction of motion of the body remains unchanged. What is the magnitude and direction of the force?

Answer 1

Hii friend,

# Answer-
Force = 1.8 N in same direction as before.

## Explaination-
# Given-
m = 3 kg
u = 2 m/s
v = 3.5 m/s
t = 2.5 s

# Solution-
Force acting on body is given by,
F = m×a
F = m(v-u)/t
F = 3×(3.5-2)/2.5
F = 1.8 N

Force of magnitude 1.8 N acts on the body in same direction as before (in direction of velocities).

Hope that is useful...

Answer 2

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ANSWER:-

0.18 N; in the direction of motion of the body

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EXPLANATION:--

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v = u + at

=> a =( v - u)/t

= (3.5 - 2)/ 25

= 1.5/ 25

= 0.06 m/s^2

As per Newton’s second law of motion, force is given as:

F = ma = 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

I hope, this will help you

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