A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 m s⁻¹ to 3.5 m s⁻¹ in 2.5 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
Answers
# Answer-
Force = 1.8 N in same direction of motion of body.
## Explaination-
# Given-
m = 3 kg
u = 2 m/s
v = 3.5 m/s
t = 2.5 s
# Solution-
Force acting on body is given by,
F = m×a
F = m(v-u)/t
F = 3×(3.5-2)/2.5
F = 1.8 N
Force of magnitude 1.8 N acts on the body in same direction of motion of body (in direction of velocities).
Hope that is useful...
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ANSWER:-
1.8 N; in the direction of motion of the body
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EXPLANATION:--
Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 2.5 s
Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:
v = u + at
=> a =( v - u)/t
= (3.5 - 2)/ 2.5
= 1.5/ 2.5
= 0.6 m/s^2
As per Newton’s second law of motion, force is given as:
F = ma = 3 × 0.6 = 1.8 N
Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.
I hope, this will help you
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