Question

A constant force acting on a body of mass 3 kg changes its speed from 2m to 3.5m in 25seconds what is the magnitude and direction of force

Answer 1

Magnitude of the force is 0.18N and its direction is the same as the direction of motion of the body.
We have m = 3kg, u = 2m/s, v = 3.5m/s and t = 25s.
Using the equation v = u+at, we get a = $\frac{v-u}{t}$
Substituting the given values for v, u and t, a = 0.06m/s².
Finally, substituting this value for a in F = ma, we get F = 3×0.06 = 0.18N.
Clearly, this force is in the same direction as that of the motion of the body.

Answer 2

Hey mate!!

Mass (m) = 3 kg

Initial velocity (u) = 2m/s

Final velocity (v) = 3.5 m/s

Time (t) = 25s

v = u + at

3.5 = 2 +a(25)

25a = 1.5

a = 0.06 m/s²

F = ma

F = 3 × 0.06

F = 0.18 N

Direction of force will be is toward the direction of motion.