Question

. A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 25 s in the direction of the motion of the body. What is the magnitude and direction of the force?

Answer 1

Mass (m) = 3 kg

Initial velocity (u) = 2m/s

Final velocity (v) = 3.5 m/s

Time (t) = 25s

v = u + at

3.5 = 2 +a(25)

25a = 1.5

a = 0.06 m/s²

F = ma

F = 3 × 0.06

F = 0.18 N

Direction of force will be is toward the direction of motion.

hope this helps

Answer 2

$\star\:{\underline{\underline{\tt{\red{GIVEN}}}}}:-$

$\tiny\:\:\:\:\bullet\:\:\:\sf\orange{Mass \:of\: the\: body\:( m ) = 3 kg}\\ \tiny\:\:\:\:\bullet\:\:\:\sf\green{The\: initial\: speed\: of \:the \:body\:(u) = 2m/s}\\\tiny \:\:\:\:\bullet\:\:\:\sf\blue{The \:final \:speed of \:the \:body\:(v) = 3.5m/s}\\\tiny \:\:\:\:\bullet\:\:\:\sf\purple{Time\: taken \ ( t )= 25 s}$

$\star\:{\underline{\underline{\tt{\orange{TO\: FIND }}}}}:-$

$\tiny\:\:\:\:\bullet\:\:\:\sf\gray{Magnitude \:and \:direction \:of\: the \:force}$

$\star\:{\underline{\underline{\tt{\blue{SOLUTION}}}}}:-$

$\red{\underline{\boxed{\sf{v = u + at}}}}$

$\dag\:\underline{\mathfrak{\purple{Substituting \: the \: values}}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{a = \dfrac{v-u}{t}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ a = \dfrac{3.5-2}{25}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{a = \dfrac{1.5}{25}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ a =0.06 m/s^{2}}$

$\red{\underline{\boxed{\sf{F=ma}}}}$

$\dag\:\underline{\mathfrak{\purple{Substituting \: the \: values}}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{3\times 0.06}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ 0.18\:N}$