Question

a constant force acting on body of 3.0 kg changes period from 2.0 M per second to 3.5 M per second in 25 seconds the direction of motion of body remains unchanged what is the magnitude of force in Newtons ?

Answer 1

u= 2 m/s
v= 3.5 m/s
t= 25 secs
m= 3 kg

a= v-u/t
a=1.5/25 m/s^2

F= ma= 3*1.5/25 N

Answer 2

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ANSWER:-

0.18 N; in the direction of motion of the body

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EXPLANATION:--

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v = u + at

=> a =( v - u)/t

= (3.5 - 2)/ 25

= 1.5/ 25

= 0.06 m/s^2

As per Newton’s second law of motion, force is given as:

F = ma = 3 × 0.06 = 0.18 N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

I hope, this will help you

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