Question

A constant force acts for 0:5s on a body of mass 1.5 kg initially at rest. When the force ceases to
act, the body is found to travel a distance of 5.0 m in 2.0 s in the direction of the force. Find the
magnitude of the force applied.
a) 22.5N
b) 5N
c) 7.5N
d) 10N
097.50​

Answer 1

Answer:

its

c) 7.5

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Answer 2

Answer:

correct answer is option c (7.5N)

Explanation:

• initial velocity,u=0 (since, the body is at rest)
• mass,m=1.5kg
• time,t=0.5s

magnitude of force on the object will be,

$f = ma \: \: \: \: \: \: - (1)$

so,we have to find acceleration,a, by using equation of motion,

$v = u + at \: \: \: \: \: \: - (2)$

and here,we have to find 'v'

$velocity = \frac{displacement}{time} \: \: \: \: \: \: - (3)\\ = \frac{5}{2} \\ = 2.5$

substituting 'v' in (2)

$2.5 = 0 + a \times 0.5 \\ a = 5$

substituting 'a' in (1)

$f = 1.5 \times 5 \\ = 7.5$

hope this helps..!