Question

a constant force acts on a body of mass 5 kg for a duration of 2s . it increases the velocity of the body from 3ms-1 to 7ms-1 . find the magnitude of the applied force . now if the force is applied for duration of 5s what would be the final velocity of the object​

Answer 1

ANSWER:-

Let the force be F,

Mass is M,

time for which it is accelerated = 2s

velocity is increased from 3m/s to 7m/s

so, acceleration is , a = (7-3)/2 = 2m/s²

The force applied is, F = ma = (5)(2) = 10 N

Now, the force is applied for 5s, the velocity after 5s will be,

v=u+at

=> v =3+(2)(5)

=>v=13m/s , this is final velocity.