Question

A constant force acts on a object of mass 5kg for duration of 2s . It increases the object velocity from 3 m/s to 7 m/s . find the magnitude of the applied force for a duration of 5 s , what would be the final velocity of the object​

Answer 1

Explanation:

We have,

• Mass (m) = 5Kg
• Time period (t) = 2s
• Initial velocity (u) = 3m/s
• Final velocity (v) = 7m/s

To find,

• Magnitude of force (F)
• Final velocity after 5s (v)

Solution,

Acceleration (a) = Chane in velocity/Time

• v- u/t
• 7 - 3/2
• 4/2
• 2 m/s²

Force (F) = Mass × Acceleration

• 5 × 2
• 10 N

Final velocity after 5s (v) = u + at

• 3 + 2 x 5
• 3 + 10
• 13 m/s

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