Physics, asked by ranagithmalakar, 5 months ago

a constant force acts on an object of mass 10 kg for a duration of 4 Second it increase the object velocity from 6 m/s to 14 m/s find the magnitude of the applied force​

Answers

Answered by INDUS18
3

Answer:

Force = 20 Newton

Explanation:

Given

Initial velocity ( u ) = 6 m/s

Final velocity ( v ) = 14 m/s

Time ( t ) = 4 s

acceleration ( a ) = (v - u ) / t

= (14 - 6 ) / 4

= 8/ 4 = 2 m/ s²

Force ( P ) = mass × acceleration

= 10 × 2 = 20 Newton

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