a constant force acts on an object of mass 10 kg for a duration of 4 Second it increase the object velocity from 6 m/s to 14 m/s find the magnitude of the applied force
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Answer:
Force = 20 Newton
Explanation:
Given
Initial velocity ( u ) = 6 m/s
Final velocity ( v ) = 14 m/s
Time ( t ) = 4 s
acceleration ( a ) = (v - u ) / t
= (14 - 6 ) / 4
= 8/ 4 = 2 m/ s²
Force ( P ) = mass × acceleration
= 10 × 2 = 20 Newton
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