Physics, asked by reliance4200, 1 year ago

A constant force acts on an object of mass 10kg for a duration of 4seconds. It Increases the object velocity from 2ms-1 to 8ms-1. Find the magnitude of the applied force


Answers

Answered by charu536
8

force=m (v-u)/t

=10(8-2) 4=10×6/4=60/4=15 n is your answer.

Answered by saratgarnayak07
2

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