Question

A constant force acts on an object of mass 10kg for a duration of 4s. If the objects velocity increases from 5m/s to 10m/s find the magnitude of force.

Answer 1

Answer:

13m/s

Explanation:

Given,

mass=5kg

t  

1

​  

=2s

Initial velocity u=3m/s

Final velocity v=7m/s

t  

2

​  

=5s

So,

Let the Force be F

Let the acceleration be a

So,

a=  

t

(v−u)

​  

=  

2

(7−3)

​  

=2m/s  

2

 

 

So the magnitude of the applied force is 10N

And the final velocity after 5s is v  

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s