A constant force acts on an object of mass 5 kg for a duration of 2 s. It increases the objects velocity from 3 m/s to 7m/s . Find the magnitude of the applied force l. Now , if the force was applied for a duration of 5s, what would be the final velocity of the object?????
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calculate acceleration = v-u/t
= 7-3/2
=4/2
=2
Using relation
F= ma= 5×2= 10 N
If force is applied for 5 sec
a=v-u/t
v= u+at = 3 + 2× 5= 13 m/s
calculate acceleration = v-u/t
= 7-3/2
=4/2
=2
Using relation
F= ma= 5×2= 10 N
If force is applied for 5 sec
a=v-u/t
v= u+at = 3 + 2× 5= 13 m/s
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i just done silly mistake so i gt wrong ans
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