Question

A constant force acts on an object of mass 5 kg for a duration of 2sec it increases the velocity front 3 m/s to 7 m/ s find the of the applied force. now if the force was applied for a duration of 5 sec what would be the final velocity of object.

Answer 1

Let the force be F,

Mass is M,

time for which it is accelerated = 2s

velocity is increased from 3m/s to 7m/s

so, acceleration is , a = (7-3)/2 = 2m/s²

The force applied is, F = ma = (5)(2) = 10 N

Now, the force is applied for 5s, the velocity after 5s will be,

v=u+at

=> v =3+(2)(5)

=>v=13m/s , this is final velocity.