Question

a constant force acts on an object of mass 5 kg for a duration of 2s it increases the objects velocity from 3ms-1 to 7ms-1 if the force was applied for a duration of 5s what would be the final velocity of the object pls show how to solve

Answer 1

Answer:

Apply the value of uand vin the equation (1), a=(7−32)ms−2. Hence, acceleration a=2ms−2. Hence, the final velocity of the object after 5 seconds is 13ms−1.

Explanation:

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