Question

A constant force acts on an object of mass 5 KG for a duration of 2s. It increases the objects velocity from 3m/s to 7m/s Find Acceleration?

Answer 1

Answer:

2 m/s²

Explanation:

As per the provided information in the given question, we have :

• Mass of the object (m) = 5 kg
• Time taken (t) = 2 s
• Initial velocity (u) = 3 m/s
• Final velocity (v) = 7 m/s

We've been asked to calculate the acceleration.

Acceleration is nothing but the rate of change in velocity. Its SI unit is m/s². It is a vector quantity that means it requires both magnitude and direction. Negative acceleration is called retardation. Retardation is also known as deceleration. Acceleration is given by,

$\qquad \qquad \qquad \Bigg [ \sf a = \dfrac{v - u}{t} \Bigg ]$

a denotes acceleration

v denotes final velocity

u denotes initial velocity

t denotes time

Now, coming back to the question again!

Substitute the values in the formula of acceleration,

$\mapsto \sf {a = \dfrac{(7 - 3)\; ms^{-1}}{2 \; s} }$

$\mapsto \sf {a = \cancel{\dfrac{4\; ms^{-1}}{2 \; s} }}$

$\mapsto \boxed{\red{ \sf{ a = 2 \; ms^{-2} }}}$

Therefore, acceleration is 2 m/s².

$\rule{200}2$

Answer 2

Given :

• ➤Initial velocity, u = 3 m/s
• ➤Final velocity, v = 7 m/s
• ➤Time, t = 2 seconds
• ➤Mass of an object, m = 5 kg

To find :

• Acceleration( a )=?

Solution :

According to the question,

• By using Newtons first equation of motion we will find acceleration

formula used

${ \underline{ \boxed{ \bf{ \red{ v = u + at}}}}} \: \: \: \: \bigstar$

Where,

• ⚘v = Final velocity
• ⚘u = Initial velocity
• ⚘a = Acceleration
• ⚘t = Time

Now, Substituting the values,

$:\implies\sf\: 7 = 3 + a × 2$

$:\implies\sf\: 7 - 3 = 2a$

$:\implies\sf\: 4 = 2a$

$:\implies\sf\: 4 ÷ 2 = a$

$:\implies\sf\: 2 = a$

hence,

the acceleration is 2 m/s².