Question

A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases object velocity from 3m/s to 7 m/s.
Find

(i) the magnitude of the force applied.
(ii) the final velocity of the force when same force is applied for 5 seconds.

Answer 1

Here is Your Answer. .....

Answer 2

Let the Force be F

mass = 5 kg

time(t)=2s

initial velocity(u) = 3 m/s

final velocity(v) =7 m/s

so let the acceleration be a
so a=(v-u)/t=(7-3)/2=2m/s^2

So the magnitude of the applied force
is 1ON

and the final velocity after 5 s is v
so v=u+at
v=3+2x5
v=13 m/s

The final velocity after 5 s is 13 m/s^2.