Question

a constant force acts on an object of mass 5 kg for duration of 2 seconds. it increases the object's velocity from 3cm/s to 7m/s . find the magnitude of the applied force. Now if the force were applied for a duration of 5s what would be the final velocity of the object ​

Answer 1

Answer:

final velocity is 13 m/s

Explanation:

mass = 5kg

time = 2sec

u= 3m/s

v = 7m/s

a= v-u/t

a= 2m/s

F= ma. F = 5*2= 10

v = u+at

= 3+2*5

= 13ms-1