a constant force acts on an object of mass 5 kg for the duration of 2 sec. it increases the velocity from 3m/s to 7m/s. find the magnitude of the applied force find acc and u in 10sec
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mass= 5 kg, time= 2 secs, u= 3m/s, v= 7m/s.
a= v-u/t, a = 7-3/2, a= 4/2, a= 2 m/s ^2
F= ma, F= (5*2) N, F= 10N.
a= v-u/t, a= 7-3/ 10,a= 2/5m/s^2.
v=u+at
7= u+ 2/5*10
7=u+ 2*2
7=u+ 4
u= 3 m/s.
a= v-u/t, a = 7-3/2, a= 4/2, a= 2 m/s ^2
F= ma, F= (5*2) N, F= 10N.
a= v-u/t, a= 7-3/ 10,a= 2/5m/s^2.
v=u+at
7= u+ 2/5*10
7=u+ 2*2
7=u+ 4
u= 3 m/s.
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