Science, asked by gaikwadtanesh167, 2 months ago

A constant force acts on an object of mass 5 kgs for 2 second If the velocity is increased from 3m/s to 7m/s. find the magnitude of force applied.​

Answers

Answered by Anonymous
3

Answer:

Apply the value of uand vin the equation (1), a=(7−32)ms−2. Hence, acceleration a=2ms−2. Hence, the final velocity of the object after 5 seconds is 13ms−1.

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