a constant force acts on an object of mass 500 for a duration of 2 sec and increases its velocity from 3m/s to 7m/s. find the force required .now if the same force was applied for a duration of 5sec. what would be the final velocity of the object
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heya.........
Let the Force be F mass = 500 kg
time(t) = 2 s
initial velocity(u) = 3 m/s
final velocity(v) = 7 m/s
so let the acceleration be a
so a = (v - u)/t = (7 - 3)/2 = 2 m/s²
So the magnitude of the applied force is 1000 N.........f=ma=500×2=1000
and the final velocity after 5 s is v
so v = u + at v = 3 + 2 x 5v = 13 m/s
The final velocity after 5 s is 13 m/s
tysm........@gozmit
Let the Force be F mass = 500 kg
time(t) = 2 s
initial velocity(u) = 3 m/s
final velocity(v) = 7 m/s
so let the acceleration be a
so a = (v - u)/t = (7 - 3)/2 = 2 m/s²
So the magnitude of the applied force is 1000 N.........f=ma=500×2=1000
and the final velocity after 5 s is v
so v = u + at v = 3 + 2 x 5v = 13 m/s
The final velocity after 5 s is 13 m/s
tysm........@gozmit
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